Permutations and combinatorics?

ok so consider the vowels to be all identitcal. also consider the all the consonants to be 1 peice. so now u have 4 letters, 3 identical and 1 different. the permutation of this is 4!/3! but in the 1 unique there are 5! ways to arrange the consonants inside the pack. so for each of the 4!/3! arrange there is another 5!. therefore thereare 4!5!/3! number of ways.